-12x^2+80x+128=0

Solution for -12x^2+80x+128=0 equation:

-12x^2+80x+128=0

a = -12; b = 80; c = +128;
Δ = b2-4ac
Δ = 802-4·(-12)·128
Δ = 12544
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{12544}=112$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-112}{2*-12}=\frac{-192}{-24}
=+8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+112}{2*-12}=\frac{32}{-24}
=-1+1/3
$